want help in solving these questions

1.A pen, pencil and eraser together cost $1.00. if 2E<N if N>2P and 3P>4E then whats the cost of a single pen???

2. At 6'o a clock ticks 6 times. The time between first and last ticks is 30 seconds. How long does it tick at 12'o clock.

Ans: 66 sec.

But 60 seconds sounds more logical but its given in the book as 66 secs,could someone tell me how its 66?

Can someone help me out in solving this...............

Spoiler

spoiler

q1 - what's an n and what's a p??

q2 - there are 5 gaps in 6 ticks, so each gap is 6 seconds there are 11 gaps in 12 ticks, at 6 seconds each that's 66seconds

It would help to know which of P, E, and N represents the pen.

If you assume that the ticks take the time, and the intervals between the ticks are negligible, then your answer is right. If you assume that the ticks take negligible time, and that there are pauses between them, then the book's answer is right.

The time ->between<- ticks is 30/5 seconds not 30/6 seconds.

Is this the actual full question? Assuming N=pen, P=pencil, E=eraser There does not appear to be a single (arithmetic) answer

The trick is to consider the number of spaces (or gaps / time periods) between the chimes (tick?) of the clock. These are where the time passes (assuming that we don't count the length of each chime )

For 6 o'clock, the clock chimes 6 times over a period of 30 seconds The 30 seconds doesn't start until the first chime has sounded This leaves 5 more 'periods' with a chime at the end of each Then 30 seconds divided by 5 periods = 6 seconds per period

Try a picture of this where ’is the tick (chime) of the clock ’ 6 seconds ’ 6 seconds ’ 6 seconds ’ 6 seconds ’ 6 seconds ’

Thus for 12 o'clock, the clock strikes or chimes 12 times The timed spaces (11) are one less than the number of chimes

Draw this out for yourself to check

Hope that helps the homework

And if you ever get a question about the number of fence posts required for a certain length of fencing where there is a nominated gap between the posts, the same approach applies

Kind regards

Eh? Then a pen, pencil and eraser together would cost 26 cents, not $1.00.

rearranging gives: P + E + N = 100 4E < 3P < 4P < 2N

There are 310 solutions to this, so you can only provide a *range* for the price of the pen without further information.

From the results: for smallest P or E: P=2 E=1 N=97 for biggest P: P=32 E=3 N=65 for biggest E: P=26 E=19 N=55

If you said you could buy any of these items using only nickels (5c), there are still 9 possible answers (in the form [P,E,N]): [10,5,85], [15,5,80], [15,10,75], [20,5,75], [20,10,70], [25,5,70], [25,10,65], [25,15,60] or [30,5,65]

The puzzle would be better if you said the total was 10c, not $1.00.

C code: #include <stdio.h> void main(void) { int p,e,n; for (p=1;p<99;p++) for (e=1;e<99;e++) { n=100-p-e; if (n>0 && (4*e<3*p) && (4*p<2*n) ) printf('p=%d e=%d n=%dn',p,e,n); }

As others have said, you are measuring the GAPS between ticks. ie, 6 o'clock is 5 gaps, therefore 6s/gap 12 o'clock is 11 gaps, therefore 66s.