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paydayuscf
 Senior Boarder
Posts: 79 
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What will the following program print?
int array[5] = {0, 1, 2, 3, 4}; main() { int x = 2; if (array[x++]
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Atraxani
Senior Boarder
Posts: 78
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It might print 'They are equal.' or 'They are not equal.', depending on the order of evaluation of array[x++]
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davidm
Senior Boarder
Posts: 65
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Actually, it's worse than that - it's undefined. In theory, the underlying machine could be half-way through incrementing x when it decides to process array[x], so you might get some sort of access violation.
And making the obvious correction, you get the same range of responses.
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Via Caltha
Expert Boarder
Posts: 85
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Indeed. My compiler warns of such.
Quite right. However by assuming the closing parenthesis just before the equality comparison, it compiles and the result of both programs (at least on my platform with my compiler) is that they both say not
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Lindy
Senior Boarder
Posts: 74
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The result is undefined and therefore implementation-dependant. As is the result of your other program.
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