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We're looking for people to help with the main blog. If you are consistent, knowledgeable and you're into it, please drop me a note.
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Transhumanist
Senior Boarder
Posts: 69
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Hi,
Below are the list of puzzles * i have tried bt could not solve, Please solve it and explain it.
1. There are two balls touching each other circumferentially. The radius of the big ball is 4 times the diameter of the small ball. The outer small ball rotates in anticlockwise direction circumferentially over the bigger one at the rate of 16 rev/sec. The bigger wheel also rotates anticlockwise at Nrev/sec. what is 'N' for the horizontal line from the centre of small wheel always is horizontal.
2.A fly is there 1 feet below the ceiling right across a wall length is 30m at equal distance from both the ends. There is a spider 1 feet above floor right across the long wall eqi distant from both the ends. If the width of the room is 12m and 12m, what distance is to be traveled by the spider to catch the fly? if it takes the shortest path.
3) Ramesh sit around a round table with some other men. He has one rupee more than his right person and this person in turn has 1 rupee more than the person to his right and so on, Ramesh decided to give 1 rupee to his right & he in turn 2 rupees to his right and 3 rupees to his right & so on. This process went on till a person has 'no money' to give to his right. At this time he has 4 times the money to his right person. How many men are there along with Ramesh and what is the money with poorest fellow.
4) 8 x 8 chess board. probability of taking two number of 3 squares diagonally = ? Reg
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swasta
Expert Boarder
Posts: 81
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Do you mean that the small ball 'rolls' around the bigger one?
Does the center point of the big ball stay in the same position? (i.e. does the big ball have another other motion besides rotation?)
Since both balls are rotating counterclockwise, at least one of the balls must have some motion in addition to rotation (assuming that there is no slippage in the contact between the balls
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Dolemite
Senior Boarder
Posts: 77
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The solution on how i interpreted the problem. Ans: The poorest fellow has Rs 2/- there are total 7 men. The start is from 8 7 6 5 4 3 2 The end is at 5 4 3 2 1 0 20 the last fellow has Rs 20/- but he need to give Rs. 21/- to first person.
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