My Profile

Keep Up to Date:
Blog RSS
Blog
Forum RSS
Forum
Search

Buy & Sell

Used (Like New) $20

Post New Topic Post Reply
Posted 9 Months, 2 Weeks ago
imported_Adrian
Senior Boarder
Posts: 72
graphgraph
User Offline
 
What's the matter? Surely this isn't too hard? (*Is* this too hard?)
The administrator has disabled public write access.
Posted 9 Months, 2 Weeks ago
querty
Senior Boarder
Posts: 73
graphgraph
User Offline
 
12, 22, 30, 36, 40, 42, 42 144, 110, 80, 54, 32, 14, 0 144, 99, 60, 27, 0
The administrator has disabled public write access.
Posted 9 Months, 2 Weeks ago
SrK
Senior Boarder
Posts: 48
graphgraph
User Offline
 
It's not hard at all. It's very easy to justify any of the sequences being the odd one out.
The administrator has disabled public write access.
Posted 9 Months, 2 Weeks ago
Chant Dhames
Senior Boarder
Posts: 77
graphgraph
User Offline
 
The answer I have in mind is unique, and involves a bit of lateral thinking...
The administrator has disabled public write access.
Posted 9 Months, 2 Weeks ago
JohnBStone
Senior Boarder
Posts: 70
graphgraph
User Offline
 
s

p

o

i

l

e

r

s

p

a

c

e

My answer is EDEB, which consist of letters without spaces between them, while the others consists of numbers.
The administrator has disabled public write access.
Posted 9 Months, 2 Weeks ago
davidm
Senior Boarder
Posts: 65
graphgraph
User Offline
 
I have three possible answers, based on your 'odd one out' clue:

Answer 1: '144, 99, 60, 27' is the odd one out, because it contains some odd numbers, while the other two sequences contain only even numbers.

Answer 2: '12, 22, 30, 36, 40, 42, 42' is the odd one out, because it has an odd length, while the other two sequences have even lengths.

Answer 3: '144, 110, 80, 54, 32, 14' is the odd one out, because there is nothing odd about it, while the other two sequences have the odd properties mentioned above.

Bob H
The administrator has disabled public write access.
Posted 9 Months, 2 Weeks ago
KlSwena
Senior Boarder
Posts: 70
graphgraph
User Offline
 
Devious, Nis, but not the answer I'm looking for...

Try making up a series of multiplication tables.
The administrator has disabled public write access.
Posted 9 Months, 2 Weeks ago
Via Caltha
Expert Boarder
Posts: 85
graphgraph
User Offline
 
S

P

O

I

L

E

R

S

P

O

I

L

E

R

S

P

O

I

L

E

R

S

P

O

I

L

E

R

S

P

O

I

L

E

R

12*1, 11*2, 10*3, 9*4, 8*5, 7*6, 6*7

12*12, 11*10, 10*8, 9*6, 8*4, 7*2

12*12, 11*9, 10*6, 9*3

The first is the odd one out as it has one of the terms increasing...
The administrator has disabled public write access.
Posted 9 Months, 2 Weeks ago
imported_Adrian
Senior Boarder
Posts: 72
graphgraph
User Offline
 
The second is the ODD one out as it has an EVEN increment (-2) for one of its subterm sequences
The administrator has disabled public write access.
Posted 9 Months, 2 Weeks ago
NGR
Senior Boarder
Posts: 64
graphgraph
User Offline
 
'Edgar De Blieck' wrote

Prolly better though
The administrator has disabled public write access.
Posted 9 Months, 2 Weeks ago
MishaEE
Senior Boarder
Posts: 63
graphgraph
User Offline
 
The first is the odd one out as it's the only one without zero as the next in the sequence.

Your turn
The administrator has disabled public write access.
 
Copyright © 2006 - Jan 2009 Fun Quizzes Club