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An exhaustive computer search gives the following two sequences of a(k)'s:
(2, 2, 1, 2, 3, 2, 4, 5, 3, 2, 4, 3) and (2, 2, 1, 2, 3, 2, 4, 5, 4, 2, 4, 2).
It would be interesting to know how many possible arrangements there are, as a function of the upper bound to the a(k)'s. Obviously, if the upper bound is 1 (i.e. 1 <= a(k) <= 1), then there is only one possible arrangement. Is it possible to reach any arrangement if the upper bound is high enough? (An upper bound of 5 is definitely too small, since 5^12 < 12!.)
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